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f3 mth questions!!!急~聽日要交!
(a) The median of the data set x,37,48 and 19 is 30. Find the value of x.Hence find the mean of these four numbers.ANS : x = 23,mean = 31.75(b)If a number y is added to the data set in part (a),the median remains uncharged. Find the value of y and the mean of these five numbers.ANS : y = 30,mean = 31.4(c)If... 顯示更多 (a) The median of the data set x,37,48 and 19 is 30. Find the value of x.Hence find the mean of these four numbers. ANS : x = 23,mean = 31.75 (b)If a number y is added to the data set in part (a),the median remains uncharged. Find the value of y and the mean of these five numbers. ANS : y = 30,mean = 31.4 (c)If another y is added to the set of five numbers in part (b),will the median and the mean charge?Why? ANS : The median will not change,but the mean will charge. *睇唔明英文版,可問我拎中文版! 求step,thx~~ 一定要有完整啲step~~唔好亂做,要同個ans一樣,一定要岩同埋要清楚(要睇得明你寫咩)!!!!thx~~~
最佳解答:
a)The data set is (19 , x , 37 , 48)(x + 37)/2 = 30x = 23mean = (19 + 23 + 37 + 48)/4 = 31.75 b)The data set must be (19 , 23 , y , 37 , 48) otherwise the median will not be 30.So the median = y = 30The mean = (19 + 23 + 30 + 37 + 48)/5 = 31.4 c)The data set must be (19 , 23 , y , y , 37 , 48)The median = (y + y)/2 = y = 30 remain unchange , but the mean will change (decrease) since y = 30 is less then the old mean 31.4.
其他解答:
(a)19,x,37,48 madian=(x+37)/2=30 =23 mean=(19+23+37+48)/4 =31.75 (b)because median remain unchange,so y must be30 mean=(19+23+30+37+48)/5 =31.4 (c)median(19,23,30,30,37,48)=(30+30)/2=30 mean=(19+23+30+30+37+48)/5 =31.4 so the median and the mean remain unchange 2011-01-10 16:14:21 補充： 呢個先至正確 (a)19,x,37,48 madian=(x+37)/2=30 =23 mean=(19+23+37+48)/4 =31.75 (b)because median remain unchange,so y must be30 mean=(19+23+30+37+48)/5 =31.4 (c)median(19,23,30,30,37,48)=(30+30)/2=30 mean=(19+23+30+30+37+48)/5 =37.4 so the median remain unchange and the mean is change
f3 mth questions!!!急~聽日要交!
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發問:(a) The median of the data set x,37,48 and 19 is 30. Find the value of x.Hence find the mean of these four numbers.ANS : x = 23,mean = 31.75(b)If a number y is added to the data set in part (a),the median remains uncharged. Find the value of y and the mean of these five numbers.ANS : y = 30,mean = 31.4(c)If... 顯示更多 (a) The median of the data set x,37,48 and 19 is 30. Find the value of x.Hence find the mean of these four numbers. ANS : x = 23,mean = 31.75 (b)If a number y is added to the data set in part (a),the median remains uncharged. Find the value of y and the mean of these five numbers. ANS : y = 30,mean = 31.4 (c)If another y is added to the set of five numbers in part (b),will the median and the mean charge?Why? ANS : The median will not change,but the mean will charge. *睇唔明英文版,可問我拎中文版! 求step,thx~~ 一定要有完整啲step~~唔好亂做,要同個ans一樣,一定要岩同埋要清楚(要睇得明你寫咩)!!!!thx~~~
最佳解答:
a)The data set is (19 , x , 37 , 48)(x + 37)/2 = 30x = 23mean = (19 + 23 + 37 + 48)/4 = 31.75 b)The data set must be (19 , 23 , y , 37 , 48) otherwise the median will not be 30.So the median = y = 30The mean = (19 + 23 + 30 + 37 + 48)/5 = 31.4 c)The data set must be (19 , 23 , y , y , 37 , 48)The median = (y + y)/2 = y = 30 remain unchange , but the mean will change (decrease) since y = 30 is less then the old mean 31.4.
其他解答:
(a)19,x,37,48 madian=(x+37)/2=30 =23 mean=(19+23+37+48)/4 =31.75 (b)because median remain unchange,so y must be30 mean=(19+23+30+37+48)/5 =31.4 (c)median(19,23,30,30,37,48)=(30+30)/2=30 mean=(19+23+30+30+37+48)/5 =31.4 so the median and the mean remain unchange 2011-01-10 16:14:21 補充： 呢個先至正確 (a)19,x,37,48 madian=(x+37)/2=30 =23 mean=(19+23+37+48)/4 =31.75 (b)because median remain unchange,so y must be30 mean=(19+23+30+37+48)/5 =31.4 (c)median(19,23,30,30,37,48)=(30+30)/2=30 mean=(19+23+30+30+37+48)/5 =37.4 so the median remain unchange and the mean is change
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