標題:
physic 問題 快進!!!!!!!(3) help me
發問:
最佳解答:
HI BY C=Q/delta(個三角形)T C=0.5x4200x58/(58-26) C=121800/32 C=3806.25 =3806j c^-1(corect to nearest integer)
其他解答:
The question ask for heat capacity ,but your answer is in terms of specific heat capacity.There must be something wrong.|||||Let H be the heat capacity of the thermometer hence, heat gained by thermometer = H.(58-26) = 32H Heat lost by the water = 0.5 x 4200 x (60 - 58) J = 4200 J Assume no heat lost to the surroundings, 32H = 4200 i.e. H = 4200/32 J/C = 131 J/C [Your given answer is probably wrong as it is a value for the specific heat capacity, but you are asked to find the "heat capacity" of the termometer]. 2011-06-11 14:55:41 補充： I still don't think your answer of 3806 J/C is right. The value seems too high and is not realistic. A practical thermometer should have a low heat capacity so as to give an accurate temperature reading.|||||The mass of the thermometer should also be provided.
physic 問題 快進!!!!!!!(3) help me
發問:
此文章來自奇摩知識+如有不便請留言告知
A thermometer is put into a cup of water of mass 0.5kg at 60*c(c=4200Jkgc).The thermometer records a temperature of 58*c a.) Find the heat capacity of the thermomter if the room temperature is 26*c the answer is 3806 Jkg -1c-1 更新: sorry the answer is 3806J*c-1 更新 2: so 131 J/C is wrong but thx forr help 更新 3: No ,I had checked many time la, no mistake ,is your answer wrong ,sorry ,it's ok,^^最佳解答:
HI BY C=Q/delta(個三角形)T C=0.5x4200x58/(58-26) C=121800/32 C=3806.25 =3806j c^-1(corect to nearest integer)
其他解答:
The question ask for heat capacity ,but your answer is in terms of specific heat capacity.There must be something wrong.|||||Let H be the heat capacity of the thermometer hence, heat gained by thermometer = H.(58-26) = 32H Heat lost by the water = 0.5 x 4200 x (60 - 58) J = 4200 J Assume no heat lost to the surroundings, 32H = 4200 i.e. H = 4200/32 J/C = 131 J/C [Your given answer is probably wrong as it is a value for the specific heat capacity, but you are asked to find the "heat capacity" of the termometer]. 2011-06-11 14:55:41 補充： I still don't think your answer of 3806 J/C is right. The value seems too high and is not realistic. A practical thermometer should have a low heat capacity so as to give an accurate temperature reading.|||||The mass of the thermometer should also be provided.
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