標題:
問PHY 1998 CE MC Q.6 AND Q.7
發問:
問PHY 1998 CE MC Q.6 AND Q.7 可唔可以解釋下個答案問黎?
6. Since the car is travelling at a uniform velocity, so by Newton's 1st law of motion, the resultant force on the car is zero. Since the frictional force acting on the car is 500 N, which is opposing the motion. So, the tension in the cable is 500 N too. So, B is the answer. 7. 圖片參考：http://i182.photobucket.com/albums/x4/A_Hepburn_1990/Mathscircle.jpg?t=1183709256 So, the resultant force = √[(4)2 + (2)2] = 4.5 N
其他解答:
問PHY 1998 CE MC Q.6 AND Q.7
發問:
問PHY 1998 CE MC Q.6 AND Q.7 可唔可以解釋下個答案問黎?
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最佳解答:6. Since the car is travelling at a uniform velocity, so by Newton's 1st law of motion, the resultant force on the car is zero. Since the frictional force acting on the car is 500 N, which is opposing the motion. So, the tension in the cable is 500 N too. So, B is the answer. 7. 圖片參考：http://i182.photobucket.com/albums/x4/A_Hepburn_1990/Mathscircle.jpg?t=1183709256 So, the resultant force = √[(4)2 + (2)2] = 4.5 N
其他解答:
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