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https://i.na.cx/P741K1.jpg part C

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13. (a) The circular frustum is made by cutting off a smaller cone from a larger cone. The diameter and height of the larger cone are 16 cm and x cm respectively. Diameter of the smaller cone = Diameter of the cylinder = 8 cm The larger cone and smaller cone are similar in shape. (x cm) : (The height of the smaller cone) = (16 cm) : (8 cm) Height of the smaller cone = 8x/16 cm = x/2 cm Height of the circular frustum = [x - (x/2)] cm = x/2 cm (b) Volume of the cylinder = (Base area) * Height = [π * (8/2)2] * [20 - (x/2)] cm3 = (320π - 8πx) cm3 (c) Volume of the circular frustum = (Volume of the large cone) - (Volume of the smaller cone) = (1/3) * π * (16/2)2 * x - (1/3) * π * (8/2)2 * (x/2)cm3 = (64/3)πx - (8/3)πx cm3 = (56/3)πx cm3 Volume of container ≥ 2L = 2000 cm3 320π - 8πx + (56/3)πx ≥ 2000 (32/3)πx ≥ 2000 - 320π πx ≥ 187.5 - 30π x ≥ (187.5 - 30π) / π

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